Los Angeles (DIYA TV) — American Idol hopeful Sonika Vaid on Thursday advanced to the top 10 in the final season of the singing competition. Just 14 contestants remained heading into the live episode, four were eliminated; Vaid, an Indian American from Martha’s Vineyard, stood tall as one of the 10 who advanced.
“The way your voice sits in the music is so out of this world,” judge Jennifer Lopez said, adding Vaid has a “voice from God.”
On Thursday, Vaid performed “Bring Me to Life” by Evanesence, a performance of which left the crowd, and likely the viewers, in shock and awe. She also sung a rendition of Celine Dion’s “I Surrender,” which drew rave reviews. Celebrity chef Gordon Ramsay had this to say of Vaid’s voice:
Wow what a voice https://t.co/9Y79gkXeHt
— Gordon Ramsay (@GordonRamsay) February 25, 2016
We were so moved by @sonikavaid's powerful rendition of “Bring Me to Life” by @evanescence.https://t.co/pdX9qpiH4K
— American Idol (@AmericanIdol) February 26, 2016
You may cast your vote for Vaid here, and tune into American Idol’s final season on Fox.
Don't forget to go VOTE and support @sonikavaid! #IdolTop10 https://t.co/zflQXnsvHE pic.twitter.com/7uOS6mkur5
— American Idol (@AmericanIdol) February 26, 2016
